Calculate the area of the parallelogram when adjacent sides are given by the vectors →A = ^i + 2^j + 3^k and →B = 2^i − 3^j + ^k
sq unit
We know that the area of the parallelogram is equal to the magnitude of the cross product of given vectors.
Now,
→A×→B=∣∣
∣
∣∣^i^j^k1232−31∣∣
∣
∣∣=^i(2+9)+^j(6−1)+^k(−3−4)=11^i+5^j−7^kSo area of parallelogram :|→A×→B|=√112+52+(−7)2=√195sq.unit