Question

Calculate the current through the circuit and the potential difference across the diode shown in figure. The drift current for the diode is $20\mu A.$

Answer 1

Both the resistor and diode are connected in series so the amount of current in both the of them will remain the same which is $20\mu A$.

The potential drop across resistor will be equal to,

$V=20\times {10}^{-6}\times 20$

$=0.4mV$

The potential drop across diode is thus,

$V_D=\left(5-0.4\times {10}^{-3}\right)V$

$=4.9996V$