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Question

Calculate the degree of hydrolysis of 0.01 M sodium acetate solution. Ka=1.8×105.

A
3.32×104
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B
4.24×102
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C
5.26×103
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D
None of these
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Solution

The correct option is B None of these
Ka=1.8×105, C=0.01 M

For dissociation of weak acid-
Ka=Cα2

α=KaC=1.8×1050.01=1.8×103=4.24×102

Hence, option B is correct.

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