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Question

# Calculate the difference in the net stabilization energies (in kJmol−1) of Fe2+ octahedral complexes with CN− ligands (Δ0=25000 cm−1) and with H2O ligands (Δ0=10000 cm−1). Given that the pairing energy, Ep=15000 cm−1 for Fe2+ ion in both the complexes. (Given: h = 6×10−34 Jsec, Avogadro's Number = 6×1023, Speed of light =3×108 m sec−1)

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Solution

## [Fe(CN)6]4− complex is a low spin complex with configuration t62ge0g. While [Fe(H2O)6]2+ complex is a high spin complex with configuration t42ge2g For [Fe(CN)6]4−, CFSE=−25×6×Δ0+3Ep=(−25×6×25000+3×15000) cm−1=−15000 cm−1 For [Fe(H2O)6]2+, CFSE=(−25×4+35×2)×Δ0+15000=(−0.4×10000+15000) cm−1=11000 cm−1 So, difference in CFSE = 11000−(−15000)=26000 cm−1 ⇒E=hcλ=hc¯v=(6×10−34)×(3×108)×(26000×102)×6×1023×10−3 kJ/mol = 280.80 kJ/mol

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