Question

# Calculate the energy of the light having wavelength 45 nm : [Planck's constant $$h = 6.63 \times 10^{-34} Js$$ ; speed of light $$c = 3 \times 10^8 ms^{-1}$$]

A
6.67×1015
B
6.67×1011
C
4.42×1015
D
4.42×1018

Solution

## The correct option is D $$4.42\times 10^{-18}$$The relationship between the enrgy of light and its wavelength is as given below.$$E=\dfrac {hc}{\lambda}$$Substitute values in the above expression.$$E=\dfrac {6.63\times 10^{-34}\times 3\times 10^8}{45\times 10^{-9}}=4.4\times 10^{-18}$$Hence, the energy of light corresponding to wavelength 45 nm is $$4.42\times 10^{-18}$$.Hence, the correct option is $$D$$Chemistry

Suggest Corrections

0

Similar questions
View More

People also searched for
View More