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Question

Calculate the energy of the light having wavelength 45 nm : 

[Planck's constant $$h = 6.63 \times 10^{-34} Js$$ ; speed of light $$c = 3 \times 10^8 ms^{-1}$$]


A
6.67×1015
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B
6.67×1011
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C
4.42×1015
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D
4.42×1018
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Solution

The correct option is D $$4.42\times 10^{-18}$$
The relationship between the enrgy of light and its wavelength is as given below.

$$E=\dfrac {hc}{\lambda}$$

Substitute values in the above expression.

$$E=\dfrac {6.63\times 10^{-34}\times 3\times 10^8}{45\times 10^{-9}}=4.4\times 10^{-18}$$

Hence, the energy of light corresponding to wavelength 45 nm is $$4.42\times 10^{-18}$$.

Hence, the correct option is $$D$$

Chemistry

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