Question

Calculate the equivalent mass of $H_2{SO}_4$ from the given reactions.
$\left(a\right)H_2{SO}_4+NaOH\to NaH{SO}_4+H_{2}O$
$\left(b\right)H_2{SO}_4+2NaOH\to {Na}_2{SO}_4+2H_{2}O$

• A. $49$ and $98$
• B. $98$ and $49$
• C. Both $49$
• D. Both $98$

Answer 1

Answer: (B)

$98$ and $49$

$\left(a\right)H_2{SO}_4+NaOH\to NaH{SO}_4+H_{2}O$

Number of equivalent moles in the reaction = $1$ as only 1 $H^{+}$ is involved.

$Equivalentweight=\frac{Molecularweight}{Numberofequivalentmoles}$

$\Rightarrow Equivalentweight=\frac{98}{1}=98$

$\left(b\right)H_2{SO}_4+2NaOH\to {Na}_2{SO}_4+2H_{2}O$

Number of equivalent moles in the reaction = $2$ as both $H^{+}$ are reacting with base.

$\Rightarrow Equivalentweight=\frac{98}{2}=49$