Question

# Calculate the equivalent mass of $${H}_{2}{SO}_{4}$$ from the given reactions.$$(a)\ {H}_{2}{SO}_{4}+NaOH\rightarrow NaH{SO}_{4}+{H}_{2}O$$$$(b)\ {H}_{2}{SO}_{4}+2NaOH\rightarrow {Na}_{2}{SO}_{4}+2{H}_{2}O$$

A
49 and 98
B
98 and 49
C
Both 49
D
Both 98

Solution

## The correct option is A $$98$$ and $$49$$$$(a) {H}_{2}{SO}_{4}+NaOH\rightarrow NaH{SO}_{4}+{H}_{2}O$$Number of equivalent moles in the reaction = $$1$$ as only 1 $$H^+$$ is involved.$$Equivalent\ weight= \dfrac {Molecular \ weight}{Number\ of\ equivalent \ moles}$$$$\Rightarrow Equivalent \ weight= \dfrac {98}{1} = 98$$$$(b) {H}_{2}{SO}_{4}+2NaOH\rightarrow {Na}_{2}{SO}_{4}+2{H}_{2}O$$Number of equivalent moles in the reaction = $$2$$ as both $$H^+$$ are reacting with base.$$\Rightarrow Equivalent \ weight= \dfrac {98}{2} = 49$$Chemistry

Suggest Corrections

0

Similar questions
View More

People also searched for
View More