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Question

Calculate the freezing point of a solution containing 60g of glucose (Molar mass = 180 g Mol1) in 250 g of water.
(kf of water=1.86 K kg mol1)


Solution

Tf=?,WA=60g,MA=180g,WB=250g,Kf=1.86K kg mol1

ΔTf=Kfm

TofTf=KfWA×1000MA×WB

(0C)Tf=1.86×60×1000180×250

Tf=1.86×43

Tf=0.62×4

Tf=2.48C

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