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Question

Calculate the image distance for an object of height 12 mm at a distance of 0.20 m from a concave lens of focal length 0.30 m, and state the nature and size of the image.


Solution

Object distance = u = -0.2m = -20cm
focal length = f = -0.3m = -30cm
image distance = v 


1v - 1u = 1f  
1v - 120 = 130  

1v = 120 + 130  

1v = 3260 

v = 605 = -12 cm

m = vu 

m = 1220 = 35 

m = hh 

35  = h12mm 

h'  = 12×35 

h' = 7.2 mm

Image is erect and virtual

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