Question

Calculate the magnetic moment of a divalent ion in aqueous solution if its atomic number is 25?

Answer 1

The atomic number is 25. The metal is manganese with valence shell ,electronic configuration $3d^{5}4s^2$. The divalent ion $M{n}^{2+}$ has valence shell electronic configuration $3d^{5}4s^0$. It contains five unpaired electrons.
$n=5$
It's spin only magnetic moment is
$\sqrt{n(n+2)}=\sqrt{5(5+2)}=\sqrt{35}=5.92BM$