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Question

Calculate the mass of CO2 produced by decomposing 40 g of 60 % pure limestone.
  1. 8.20 g
  2. 14.52 g
  3. 10.56 g
  4. 12.38 g


Solution

The correct option is C 10.56 g
CaCO3CaO+CO2
Mass of 60% pure CaCO3 = 60 % ×40 g = 24 g
Moles of CaCO3=given massmolar mass=24100=0.24 moles 
As per the reaction,
1 mole of CaCO3 decomposes to give 1 mole of CO2 gas 
0.24 moles of CaCO3 will give 0.24 mole of CO2.
mass of CO2  produced = 0.24×44 = 10.56 g
 

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