Calculate the mass of oxygen obtained by complete decomposition of 10 kg of pure potassium chlorate (Atomic mass K = 39, O = 16 and Cl= 35.5)

39.2 kg

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392 kg

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3.92 kg

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3 kg

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Solution

The correct option is B 39.2 kg
Complete decomposition of pure potassium chlorate is :

$2 K C l O_{3} (s) 2 \times 122.5 k g \to 2 K C l (s) + 3 O_{2} (g) 3 \times 32 k g$

Mass of $O_{2}$ obtained by $10 K g$ $K C l O_{3} = \frac{96 \times 10}{245} = 3.92 k g$

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Similar questions

K C l O_{3}

2 K C l O_{3} △ - \to 2 K C l + 3 O_{2}

4.9 g

[K = 39; O = 16; C l = 35.5]

K C l O_{3} (s) \to K C l (s) + O_{2} (g)

80 %

48 g

K = 39 u

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