Question

Calculate the mass of salt produced when 0.2M,100ml of $H_2{SO}_4$ is mixed with 0.5M, 100ml of NaOH solution:

• A. $13.33g$
• B. $2.84g$
• C. $1.02g$
• D. ${10}^3$g

Answer 1

The correct option is B $2.84g$

$H_2{SO}_4+NaOH⟶{Na}_2{SO}_4+H_{2}O$

Initial miliequt$=2\times 0.2\times 1000.5\times 12000$

$=40=50$

after neutralization $=0=50-404040$

$=10$

Total solute$=100+100=200ml$

So, normal of salt$=\frac{miliequt}{Volumeinml}=\frac{40}{200}$

=0.2N

We have 40 miliequat of ${Na}_2{SO}_4$

$=40\times {10}^{-3}equtof{Na}_2{SO}_4$

quantum of ${Na}_2{SO}_4=equatof{Na}^{+}+equatof{{SO}_4}^{2-}$

$=23+\frac{96}{2}$

$=23+48=71$

wt. of ${Na}_2{SO}_4=40\times {10}^{-3}\times 71$

wt. of ${Na}_2{SO}_4=2.84qm$