Calculate the mass percent of carbon in $C_{2} H_{5} O H$ (Molar mass of ethanol=46.068g)

13.13 %

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88.79 %

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52.14 %

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34.73 %

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Solution

The correct option is C $52.14 %$
Given : Mass of $C_{2} H_{5} O H = 46.08 g$
Molecular mass $= 46.08 g$
Percentage of carbon $= \frac{Mass of carbon}{Molecular mass} \times 100 = \frac{24}{46.08} \times 100 = 52.14 %$

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