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Question

Calculate the missing frequency from the following distribution, it being given that the median of the distribution is 24.
Class0101020203030404050
Frequency525?187

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Solution

CI Frequency c.f
0105 5
1020 25 30
2030 x 30+x
3040 18 48+x
4050 7 55+x
N=55+x
Median =24
Median class =2030
Here, l=20,h=10,f=x,cf=30,N2=55+x2
Median=l+N2cff×h

24=20+55+x230x×10

4=55+x230x×10

4x=(55+x230)×10

4x×2=(55+x60)×10
8x=550+10x600
10x8x=600550
2x=50
x=25

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