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Question

Calculate the molality of a 1 L solution of 80% H2SO4(wv), given that the density of the solution is 1.80 g mL1.

A
8.16 m
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B
8.60 m
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C
1.02 m
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D
10.8 m
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Solution

The correct option is A 8.16 m
Let the volume of the solution be 1000 mL.
The sample of H2SO4 is 80% by volume.
Hence, weight of H2SO4 = w(H2SO4) = 800 g in 1000 mL
Moles of H2SO4=given massmolar mass=80098=8.16
Weight of solution =1000×1.80=1800 g
Weight of solvent = 1800800=1000 g
Molality =Moles of soluteweight of solvent (in g)×1000
Molality =8.161000×1000=8.16 m

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