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Question

Calculate the molecular formula of the compound which contains 12% Mg and 88% Br by weight, if the molecular weight of compound is 184 g.
  1. Mg2Br
  2. Mg32Br
  3. MgBr2
  4. MgBr


Solution

The correct option is C MgBr2
Let us assume that the total weight of the compound = 100 g

Mass of Br present in the compound = 88 g
Moles of Br present in the compound,
= 8880=1.1 mol

Mass of Mg present in the compound = 12 g
Moles of Mg present in the compound,
= 1224=12 mol

The simplest whole number ratio of Mg:Br = 1 : 2
Hence, the empirical formula becomes MgBr2
The empirical formular mass =24+2×80=184
The given molecular weight of the compound = 184 g

Empirical formula mass = molecular formula mass.
Hence, the molecular formula is the same as the empirical formula.

So, the molecular formula of the compound is MgBr2.

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