The correct option is C MgBr2
Let us assume that the total weight of the compound = 100 g
Mass of Br present in the compound = 88 g
∴ Moles of Br present in the compound,
= 8880=1.1 mol
Mass of Mg present in the compound = 12 g
∴ Moles of Mg present in the compound,
= 1224=12 mol
The simplest whole number ratio of Mg:Br = 1 : 2
Hence, the empirical formula becomes MgBr2
The empirical formular mass =24+2×80=184
The given molecular weight of the compound = 184 g
Empirical formula mass = molecular formula mass.
Hence, the molecular formula is the same as the empirical formula.
So, the molecular formula of the compound is MgBr2.