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Question

Calculate the momentum of a particle which has a de Broglie wavelength of 4.5×1010 m.
(Planck's constant, h=6.6×1034 kgm2s1)

A
1.24×1024 kgms1
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B
3.24×1024 kgms1
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C
1.46×1024 kgms1
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D
2.93×1024 kgms1
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Solution

The correct option is C 1.46×1024 kgms1
Given:
de Broglie wavelength (λ)=4.5×1010 m
Planck's constant (h)=6.6×1034 Js
Let 'p' be the momentum of the particle.
We know that de Broglie wavelength is given by,
λ=hp
p=hλ=6.6×10344.5×1010=1.46×1024 kgms1

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