Question

Calculate the no.of quanta (in terms of $\times {10}^{23}$) of radiation frequency $4.67\times {10}^{13}se{c}^{-1}$, that must be absorbed to melt $10g$ ice. The energy required to melt $1g$ ice is $33J$.

• A. 0.107
• B. 0.197
• C. 1.12
• D. none of these
  

Answer 1

The correct option is A 0.107

The energy required to melt 1g ice is 33J.

The energy required to melt 10 g ice is 330J.

The radiation frequency is $4.67\times {10}^{13}se{c}^{-1}$

The energy of the radiation is $E=h\nu =6.626\times {10}^{-34}Js\times 4.67\times {10}^{13}se{c}^{-1}=3.09\times {10}^{-20}J$

The number of quanta required is $\frac{330J}{3.09\times {10}^{-20}J}=1.065\times {10}^{22}=0.107\times {10}^{23}$

So, the answer is 0.107.

Option A is correct.