Question

Calculate the number of $\alpha$ and $\beta$-particles in the change.
${}_{92}^{235}U⟶{}_{82}^{207}Pb$

• A. $7-\alpha ,4-\beta$
• B. $7-\alpha ,5-\beta$
• C. $5-\alpha ,4-\beta$
• D. none of these

Answer 1

The correct option is A $7-\alpha ,4-\beta$

number of alpha particles = differences in mass numbers / 4
= 235-207/4 = 7
number of beta particles = (2 x alpha particles) -( differences in atomic number)
= 4