    Question

# Calculate the number of electrons present in a pure sample of H2SO4 containing 8 moles of O-atoms?

A
6.022×1025
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B
3.011×1025
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C
12.044×1024
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D
6.022×1026
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Solution

## The correct option is A 6.022×1025From the formula unit of H2SO4, 4 moles of O−atoms are present in 1 mole of H2SO4. Therefore, 8 moles of O−atomes will be present in =84 moles of H2SO4 Again, the total number of electrons in one formula unit of (NH4)2SO4 =2+16+8×4=50 So, the total number of electrons in one mole of H2SO4 =50×6.022×1023 Therefore, the total number of electrons in 84 moles of H2SO4 =50×6.022×1023×2=6.022×1025  Suggest Corrections  0      Similar questions  Related Videos   Balancing of a Chemical Reaction
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