Question

Calculate the number of electrons present in a pure sample of $H_{2}S{O}_4$ containing $8$ moles of $O$-atoms?

• A. $6.022\times {10}^{25}$
• B. $3.011\times {10}^{25}$
• C. $12.044\times {10}^{24}$
• D. $6.022\times {10}^{26}$

Answer 1

The correct option is A $6.022\times {10}^{25}$

From the formula unit of $H_{2}S{O}_4$, $4$ moles of $O-$atoms are present in $1$ mole of $H_{2}S{O}_4$.

Therefore, $8$ moles of $O-$atomes will be present in
$=\frac{8}{4}$ moles of $H_{2}S{O}_4$

Again, the total number of electrons in one formula unit of $(N{H}_4{)}_{2}S{O}_4$
$=2+16+8\times 4=50$

So, the total number of electrons in one mole of $H_{2}S{O}_4$
$=50\times 6.022\times {10}^{23}$

Therefore, the total number of electrons in $\frac{8}{4}$ moles of $H_{2}S{O}_4$
$=50\times 6.022\times {10}^{23}\times 2=6.022\times {10}^{25}$