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Question

Calculate the percentage ionic character of $$HCl$$ molecule. The bond length is $$1.275 \,A^o$$ and observed dipole moment is $$1.03 \,D$$.


Solution

Given, Observed dipole moment = 1.03 D
Theoretical bond length = 4.8$$\times$$bond length
Percentage ionic character = $$\cfrac { { \mu  }_{ experimental } }{ { \mu  }_{ theoretical } } \times 100=\cfrac { 1.03 }{ 1.275\times 4.8 } \times 100\simeq 17\%$$

Chemistry

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