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Question

Calculate the percentage of free SO3 in an oleum that is labelled 118% H2SO4


A
18%
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B
40%
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C
80%
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D
72%
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Solution

The correct option is C 80%
118% H2SO4 refers to the total mass of pure H2SO4 i.e.  118 g that will be formed when 100 g of oleum will be diluted by 18 g of H2O which combines with all the free SO3 present in oluem to form H2SO4

H2O (l)+SO3 (g)H2SO4 (aq)

1 mol of H2O combines with 1 mol of SO3
or
18 g of H2O combines with 80 g of SO3
Thus 100 g of oleum contains 80 g of SO3 or 80% free SO3
 

Chemistry

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