Calculate the percentage of water of crystallization in $C u S O_{4} .5 H_{2} O (H = 1, O = 16, S = 32, C u = 64)$ .

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Solution

The molecular weight of water $H_{2} O = 2 (1) + 16 = 18 g / m o l$ .
The molecular weight of copper sulphate pentahydrate $C u S O_{4} .5 H_{2} O = 64 + 32 + 4 (16) + 5 (18) = 250 g / m o l$ .
The percentage of water of crystallization in $C u S O_{4} .5 H_{2} O = \frac{5 \times 18}{250} \times 100 = 36 %$ .

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