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Question

Calculate the pH of 0.05m NaOH solution.

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Solution

Since NaOH is base, firstly, We have to find pOH
pOH=log[0.05]

pOH=log[5×102]

pOH=[log5+2log10]

pOH=2log5 ( since log 10 =1)

pOH=20.6990

pOH=1.301

pH+pOH=14

pH=141.301

pH=12.69


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