Calculate the pressure at a depth of $50 m$ below the surface of the sea. The density of sea water is $1024 k g / m^{3}$ . Take acceleration due to gravity $g = 10 m / s^{2}$

512000 Pa

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51200 Pa

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5120 Pa

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None of these

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Solution

The correct option is A
512000 Pa

Given,

Density (d) = $1024 k g / m^{3}$ , Depth $h$ = $50 m$ and $g = 10 m / s^{2}$

The expression of pressure at the bottom of a liquid of height $h$ and density $d$ is given by $ρ g h$
Thus, pressure = $ρ g h$ = $1024 \times 50 \times 10$ = $512000 P a$

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