Calculate the pressure at a depth of 50 m below the surface of the sea. The density of sea water is 1024 kg/m³.

512000 Pa

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51200 Pa

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5120 Pa

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None of these

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Solution

The correct option is A
512000 Pa

Given,

Depth = $50 m$

Density = $1024 k g / m^{3}$

The expression of pressure at the bottom of a liquid of height ‘h’ and density ‘d’ is given by $ρ g h$ .

Thus, pressure $= ρ g h = 1024 \times 50 \times 10 = 512000 P a$ .

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Calculate the pressure at a depth of 50 m below the surface of the sea. The density of sea water is 1024 kg/m3.

The correct option is A 512000 Pa Given, Depth = 50 m Density = 1024 kg/m3 The expression of pressure at the bottom of a liquid of height ‘h’ and density ‘d’ is given by ρgh. Thus, pressure =ρgh=1024×50×10=512000Pa.

Calculate the pressure at a depth of 50 m below the surface of the sea. The density of sea water is 1024 kg/m³.

The correct option is A
512000 Pa

Given,

Depth = $50 m$

Density = $1024 k g / m^{3}$

The expression of pressure at the bottom of a liquid of height ‘h’ and density ‘d’ is given by $ρ g h$ .

Thus, pressure $= ρ g h = 1024 \times 50 \times 10 = 512000 P a$ .