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Question

Calculate the pressure at a depth of 50 m below the surface of the sea. The density of sea water ρ is 1024 kg m3.


A
612000 Pa
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B
51200 Pa
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C
5120 Pa
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D
512 Pa
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Solution

The correct option is A 612000 Pa
The expression of pressure at the bottom of a liquid of height h and density ρ is given by Po+ρgh.
The given values are:
ρ=1024 kg m3
h=50 m
g=10 ms2.
Po=105 Pa

Substituting values, pressure:
P=Po+ρgh
P=105+1024×50×10
P=612000 Pa.

Physics

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