Calculate the pressure in pascal exerted by a force of $300 N$ acting normally on an area of $30 c m^{2}$

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Solution

$F = 300 N$
$A = 30 c m^{2} = \frac{30}{100 \times 100} m^{2} = 30 \times 10^{- 4} m^{2}$
$P = \frac{F}{A} = \frac{300}{\frac{30}{100 \times 100}}$
$= \frac{300 \times 100 \times 100}{30}$
$= 100000 = 10^{5} P a$

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Calculate the pressure in pascal exerted by a force of 300 N acting normally on an area of $30 c m^{2}$ .

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