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Standard XII

Chemistry

EMF

Calculate the...

Question

Calculate the standard cell potential in (V) of the cell in which following reaction takes place:
$F e^{2 +} (a q) + A g^{+} (a q) \to F e^{3 +} (a q) + A g (s)$
Given that
$E_{A g^{+} / A g}^{o} = x V$
$E_{F e^{2 +} / F e}^{o} = y V$
$E_{F e^{3 +} / F e}^{o} = z V$

x + 2 y - 3 z

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x - z

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x - y

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x + y - z

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Solution

The correct option is A $x + 2 y - 3 z$
Solution:- (A) $x + 2 y - 3 z$

$F e^{2 +} (a q) + A g^{+} (a q) \to F e^{3 +} (a q) + A g (s)$

Cell reaction,

Anode: $F e^{2 +} (a q) \to F e^{3 +} (a q) + e^{⊖}; E_{F e^{2 +} / F e^{3 +}}^{o} = m V$

Cathode: $A g^{+} (a q) + e^{⊖} \to; A g (s); E_{A g^{+} / A g}^{o} = x V$

$\Rightarrow$ cell standard potential $= (m + x) V$

Now, to find 'm',

$F e^{2 +} + 2 e^{⊖} \to F e; E_{1}^{o} = y V \Rightarrow Δ G_{1}^{o} = (2 F y)$

$F e^{3 +} + 3 e^{⊖} \to F e; E_{2}^{o} = z V \Rightarrow Δ G_{2}^{o} = (3 F y)$

$F e^{2 +} (a q) \to F e^{3 +} (a q) + e^{⊖}; E_{3}^{o} = m V \Rightarrow Δ G_{3}^{o} = - (1 F m)$

$Δ G_{3}^{o} = Δ G_{1}^{0} - Δ G_{2}^{o} = (- 2 F y + 3 F z) = - F m$

$\Rightarrow m = (2 y - 3 z)$

$\Rightarrow E_{c e l l}^{o} = (x + 2 y - 3 z) V$

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Calculate the standard cell potential in (V) of the cell in which following reaction takes place:Fe2+(aq)+Ag+(aq)→Fe3+(aq)+Ag(s) Given thatEoAg+/Ag=xVEoFe2+/Fe=yVEoFe3+/Fe=zV

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