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Question

Calculate the standard free energy change for the reaction,
N2(g)+3H2(g)2NH3(g) at 298 K.
Given Ho=92.4 kJmol1 and So=198.3 JK1mol1

A
-85.50 kJ/mol
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B
33.31 kJ/mol
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C
-33.31 kJ/mol
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D
85.50 kJ/mol
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Solution

The correct option is C -33.31 kJ/mol
Go=HoTSo
=92.4298×(198.3)×103(So=198.3×103 kJK1mol1)
=33.306 kJ/mol
Since Go is negative, it means that a mixture of H2 and N2 at 25oC, each present at a pressure of 1 atm would react spontaneously to form ammonia.

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