Question

Calculate the sum of angles of a polygon with:​ $12$ sides

Answer 1

Given, number of sides of a polygon $\left(n\right)=12$.​

[$\because$ Sum of angles of a polygon with n sides $=(n-2)\times {180}^o]$​

Then, sum of angles $=(n-2)\times {180}^o$​

$=(12-2)\times {180}^o$

$=10\times {180}^o$​

$={1800}^o$

Hence, sum of angles of a polygon with $12$ sides is ${1800}^o$.​