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Ideal Gas Equation

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Question

Calculate the temperature of 4.0 mol of a gas occupying $5 d m^{3}$ at 3.32 bar. $(R = 0.083 b a r d m^{3} K^{- 1} m o l^{- 1})$ .

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Solution

Given,

$n = 4.0 m o l V = 5 d m^{3} p = 3.32 b a r R = 0.083 b a r d m^{3} K^{- 1} m o l^{- 1}$
The temperature (T) can be calculated using the ideal gas equation as:
$p V = n R T \Rightarrow T = \frac{p V}{n R} = \frac{3.32 \times 5}{4 \times 0.083} = 50 K$
Hence, the required temperature is 50 K.

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Ideal Gas Equation

Standard XII Chemistry

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