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Question

Calculate the time interval between 33% decay and 66% decay if half-life of a substance is 20 minutes:

A
40 minutes
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B
20 minutes
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C
60 minutes
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D
13 minutes
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Solution

The correct option is B 20 minutes
We know that,Nt=N0eλt ln(0.66N0)=λt1 ...(1)
and ln(0.33N0)=λt2 ...(2)

Equation (1) Equation (2):
λ(t2t1)=ln(0.660.33)=ln2
t2t1=ln2λ=t1/2=20 min

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