Question

Calculate the total number of electrons present in $1.6$ gm of methane.

Answer 1

Mass= $1.6gm$

Moles= $\frac{1.6}{16}=0.1$

Total number of molecules= $6.027\times {10}^{23}\times 0.1=6.023\times {10}^{22}$

Electron in $1$ molecule= $C+H\times 4\Rightarrow 6+4=10$

So in, $6.023\times {10}^{22}$ molecules $\Rightarrow 10\times 6.023\times {10}^{22}$

$\Rightarrow 6.023\times {10}^{23}$