Calculate the uncertainty in the position (Δx) of an electron if Δv is 0.1%. Take the velocity of electron =2.2×106 ms−1 and mass of electron as 9.108×10−31kg.
262.48 × 10-10 m
From Heisenberg Uncertainty Principle, we know
Δp × Δx = h4π ⇒ Δv × Δx = h4mπ
Given , Δv=0.1% of the velocity of the electron
=0.1100 ×2.2 × 106 =2.2× 103ms−1
Since Δx is much longer than the atomic diameter (≈ 10−10m), the uncertainty principle is applicable in this case.