Question

Calculate the vertical height of a mercury column which exerts a pressure of 81600 Pa. (Density of mercury is $13.6gc{m}^{-3}$ and $g=10m{s}^{-2})$.

• A. 0.2 m
• B. 0.4 m
• C. 0.6 m
• D. 0.8 m

Answer 1

The correct option is C 0.6 m

$Pressure\left(P\right)=81600Pa$
$Density\left(d\right)=13.6gc{m}^{-3}$
$=13.6\times 1000kg{m}^{-3}$
$(\therefore 1gc{m}^{-3}=1000kg{m}^{-3})$

Acceleration due to gravity $\left(g\right)=10m{s}^{-2}$
$P=hdg$
$\Rightarrow h=\frac{P}{dg}=\frac{81600}{13.6\times 1000\times 10}$
$\Rightarrow h=0.6m$
Therefore, vertical height of mercury column is 0.6 m.