Calculate the volume in litre of 0.1 M solution of HCI which contains 0.365 g HCI ?

10^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.1 L

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1 L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $0.1 L$
Molarity= $\frac{n_{s o l u t e}}{V_{s o l u t i o n}}$
$n_{s o l u t e} = \frac{0.365 g}{36.5 g m o l^{- 1}} = 0.01 m o l$ ....(given)
atomic mass of HCl is 36.5 $g {m o l}^{- 1}$
Therefore, $V_{s o l u t i o n} = \frac{0.01}{0.1} = 0.1 L$

Suggest Corrections

Similar questions

24.8 %

[H = 1, C l = 35.5]

Δ p H

N a H C O_{3}

(i n i t i a l p H = 9, K a_{1} = 10^{- 7}, K a_{2} = 10^{- 11}

H_{2} C O_{3})

{C H}_{2} C O O N a

{C H}_{2} C O O N a

Join BYJU'S Learning Program