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Question

Calculate the volume of CO2 evolved at NTP when 20g of CaCO3 is heated strongly.


A

3.38 L

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B

4.48

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C

5.58 L

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D

6.68 L

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Solution

The correct option is B

4.48


The question gives weight of reactants and asks the volume of product. So, it is a weight-volume problem. Start by balancing the reaction

CaCO3 CaO + CO2(g)

1 mole of CaCO3 gives 1 mole of CO2

From Avogadro's Law, 1 mole of CO2 at NTP occupies 22.4L

1 mole of CaCO3 = 22.4 L of CO2
100g = 22.4L of CO2

20g = 20 × 22.4100 = 4.48 L of CO2


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