Question

Calculate the volume of $C{O}_2$ evolved by the combustion of $50$ ml of a mixture containing $40$ per $C_2{H}_4$ and $60$ per $C{H}_4$ (by volume).

• A. $70$ ml
• B. $75$ ml
• C. $80$ ml
• D. $82$ ml

Answer 1

Answer: (A)

$70$ ml

The volume of $C_2{H}_4$ in $50$ ml of sample is $50ml\times \frac{40}{100}=20ml$.

The volume of $C{H}_4$ in $50$ ml of sample is $50ml\times \frac{60}{100}=30ml$.

$\underset{30ml}{C{H}_4}\to \underset{30ml}{C{O}_2}+\underset{60ml}{2H_{2}O}$

$\underset{20ml}{C_2{H}_4}\to \underset{40}{2C{O}_2}+\underset{40ml}{2H_{2}O}$
The volume of carbon dioxide formed is $30ml+40ml=70ml$.