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Molarity

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Question

Calculate the volume of concentrated sulphuric acid (molarity = 18 M) required to prepare 250 mL of 2 M acid solution.

A

27.8 mL

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B

15.4 mL

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C

20.5 mL

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D

23.6 mL

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Solution

The correct option is A 27.8 mL
As per the concept of dilution,
$M_{1} V_{1} = M_{2} V_{2} \Rightarrow (18 \times V_{1}) = (2 \times 250) \Rightarrow V_{1} = 27.8 m L$
Volume of concentrated $H_{2} S O_{4}$ required= 27.8 mL

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