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# Calculate the volume of the 80% h2so4 by weight density 1.8 /mol required to prepare 1L of 0. 2 M solution

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Solution

## Dear student, There is a little correction in the question. Density of 80% sulphuric acid would be 1.8 g/ml not 1.8g/mol. First you have to calculate the molarity of 80% acid solution which will act as stock solution. By using the given density 1.8 g/mL 1800 g for 1 litre Thus, 80% X 1800 =1440g acid required Since, molarity = weight taken/ formulae weight Weight taken=1440 and formulae weight of sulphuric acid=98.08 => 1440/98.08= 14.68 M Now molarity of stock solution 14.68M In next step we require 0.2 M acid solution from 14.68M stock solution. We can use the formulae M1* V1= M2* V2 Applying values M2=0.2 V2=1000 ml M1=14.68 volume required (V1) = (0.2 X 1000) / 14.68 =200/14.68 = 13.62 ml So 13.62 ml volume of 80 % sulphuric acid is required. Hope you understood Regards  Suggest Corrections  6      Similar questions
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