Question

Calculate the volume of water to be added to 100 mL of a 5 N solution to obtain a 0.01 N resultant solution.

• A. 49.9 L
• B. 58.7 L
• C. 62.4 L
• D. 35.9 L

Answer 1

The correct option is A 49.9 L

$N_1{V}_1=N_2{V}_2$
Where,
$N_1\Rightarrow$ Normality of the initial solution = 5 N
$V_1\Rightarrow$ Volume of the initial solution =100 mL.
$N_2\Rightarrow$ Normality of the resultant solution i.e. after dilution = 0.01 N
$V_2$⇒ Volume of the resultant solution.
$5\times 100=0.01\times V_2$
$V_2=\frac{5\times 100}{0.01}=50000$ mL
So, volume of water to be added
$=(50000–100)$ mL
= 49900 mL
= 49.9 L