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Question

Calculate the wavelength of an electron moving with a velocity of 2.05 × 107ms–1.

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Solution

According to de Broglie’s equation,
λ=hmv
Where, λ = wavelength of moving particle
m = mass of the particle
v = velocity of the particle
h = Planck’s constant
Substituting the values in the expression of λ:
λ=6.626×10−34Js

(9.10939×10−31kg)(2.05×107)ms−1
Hence, the wavelength of the electron moving with a velocity of 2.05 × 107ms–1 is 3.548 × 10–11 m.


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