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Question

Calculate the work done when 5 moles of oxygen gas contracts isothermally from 85 L  to 15 L  against a constant pressure of 2 atm at 250C.
  1. 140 L atm
  2. 70 L atm
  3. 7.0 L atm
  4. 14.0 L atm


Solution

The correct option is A 140 L atm
We know, work done for an isothermal irreversible process is given as:
w=Pext(V2V1)
where Pext= external pressure = 1 atm
V2= final volume = 15 L
V1 = initial volume = 85 L
so, (V2V1)= 70 L
w=2×70=140 L atm
 

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