Question

................ can be one of the term in Arithmetic progression 4, 7, 10, ...............

• A. 103
• B. 123
• C. 171
• D. 99

Answer 1

The correct option is A 103

The nth term of an AP is given by $t_n=a+(n-1)d$
In the given AP,
$a=4,d=3$
So,

$a+(n-1)d=4+(n-1)3$

$=4+3n-3$

$=3n+1$
Now, if we equate the first option
$103=3n-1$
we get $n=34$ which is a possible value for $n$
However, if we equate any of the other values we do not get a positive integer value of $n$.
This cannot be possible since $n$, which is the number of terms has to be a positive integer.