Question

Carry out the following division.
$9x^2{y}^2(3z-24)÷27xy(z-8)$

Answer 1

$9x^2{y}^2(3z-24)÷27xy(z-8)=\frac{9x^2{y}^2\left\{3\right(z-8\left)\right\}}{27xy(z-8)}$
Cancel out the common factors from numerator and denominator.
$\frac{9x^2{y}^2\left\{3\right(z-8\left)\right\}}{27xy(z-8)}=\frac{xy}{1}$
$=xy$
$\therefore 9x^2{y}^2(3z-24)÷27xy(z-8)=xy$