Identify X:

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Chemical Properties of Ethers

Identify X:

Question

C H_{3} - C H_{2} - C \equiv C - C H_{2} - C H_{3}

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C H_{3} - C \equiv C - C H_{2} - C H_{2} - C H_{3}

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Solution

The correct option is A $C H_{3} - C H_{2} - C \equiv C - C H_{2} - C H_{3}$
Due to unsaturation, it will give positive test with $B r_{2}$ water.
$C H_{3} - C H_{2} - C \equiv C - C H_{2} - C H_{3} O_{3} / H_{2} O_{2} - ---- \to C H_{3} C H_{2} C O O H$

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Similar questions

S_{N} 2

c o n c . H C l :

(a) C H_{3} - C H_{2} - O H A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C H_{2} - C l

(b) C H_{3} - C H_{3} | C | C H_{3} - C H_{2} O H A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C H_{1} | C | C H_{3} - C H_{2} - C H_{3}

(c) C H_{3} - O H | C | C H_{3} - C H_{3} A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C l | C | C H_{3} - C H_{3}

(d) C H_{2} = C H - C H_{2} - O H A n h y Z n C l_{2} / △ - -------- \to C H_{2} = C H - C H_{2} - C l

An alkane with molecular formula $C_{6} H_{14}$ gives two monochloro alkanes on chlorination. What is the structure of alkane?

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C ∥ C H_{2} - C H_{2} - C H_{2} - C H_{3}

$C H_{3} - C H_{2} - C H_{2} - C H_{2} - C | | C H_{2} - C H_{2} - C H_{2} - C H_{3}$

C H_{3} - C | C H_{3} H - C H_{2} - C H_{2} - O H

C H_{3} - O H | C | C H_{3} - C H_{2} - C H_{3}

C H_{3} C H_{3} | C H - O H | C H - C H_{3}

A, B, C

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