CH 3 CH 2 CH 3400-600- C - X - Y X and Y areA- ethylene- ethaneB- Hydrogen- ethyleneC- methane- ethyleneD- Hydrogen- methane

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Standard XII

Chemistry

Introduction to E2 Mechanism

CH 3 CH 2 CH ...

Question

$C H_{3} C H_{2} C H_{3} 400 - 600^{\circ} C - ------ \to X + Y$ X and Y are

ethylene, ethane

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Hydrogen, ethylene

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methane, ethylene

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Hydrogen, methane

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Solution

The correct option is C
methane, ethylene

The thermal decomposition of alkanes is known as cracking. It leads to the formation of lower alkenes, and hydrogen.

$C H_{3} C H_{2} C H_{3} (P r o p a n e) 400 - 600^{\circ} C - ------ \to C H_{4} (M e t h a n e) + C H_{2} = C H_{2} (E t h y l e n e)$

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CH3CH2CH3400−600∘C−−−−−−−→X+Y X and Y are

The correct option is C methane, ethylene The thermal decomposition of alkanes is known as cracking. It leads to the formation of lower alkenes, and hydrogen. CH3CH2CH3(Propane)400−600∘C−−−−−−−→CH4(Methane)+CH2=CH2(Ethylene)

$C H_{3} C H_{2} C H_{3} 400 - 600^{\circ} C - ------ \to X + Y$ X and Y are

The correct option is C
methane, ethylene

The thermal decomposition of alkanes is known as cracking. It leads to the formation of lower alkenes, and hydrogen.

$C H_{3} C H_{2} C H_{3} (P r o p a n e) 400 - 600^{\circ} C - ------ \to C H_{4} (M e t h a n e) + C H_{2} = C H_{2} (E t h y l e n e)$