1
Question
CH3CH2CONH2A→CH3−CH2−NH2B→CH3−CH2−OH
In the above-given reaction, A and B respectively are:
CH3CH2CONH2A→CH3−CH2−NH2B→CH3−CH2−OH
In the above-given reaction, A and B respectively are:
Open in App
Solution
The correct option is B Br2/KOH,HNO2
CH3CH2CONH2A→CH3−CH2−NH2B→CH3−CH2−OH
In the above sequence A & B respectively are Br2/KOH and HNO2
The first step is Hoffmann bromamide degradation reaction in which an amide (propanamide) is converted to an amine (ethylamine) containing one carbon atom less. The reagent A is bromine in presence of KOH. In the second step, aliphatic primary amine (ethyl amine) reacts with nitrous acid (reagent B) to form aliphatic primary alcohol (ethyl alcohol).
CH3CH2CONH2A→CH3−CH2−NH2B→CH3−CH2−OH
In the above sequence A & B respectively are Br2/KOH and HNO2
The first step is Hoffmann bromamide degradation reaction in which an amide (propanamide) is converted to an amine (ethylamine) containing one carbon atom less. The reagent A is bromine in presence of KOH. In the second step, aliphatic primary amine (ethyl amine) reacts with nitrous acid (reagent B) to form aliphatic primary alcohol (ethyl alcohol).
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
