$C H_{3} C H_{2} O H$ can be converted into $C H_{3} C H O$ by:

catalytic hydrogenation

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treatment with

L i A l H_{4}

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treatment with pyridinium chlorochromate

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treatment with

K M n O_{4}

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Solution

The correct option is D treatment with pyridinium chlorochromate
Pyridinium chlorochromate (PCC), a complex of chromium trioxide with pyridine and $H C l$ gives good yield of aldehydes and prevents further oxidation to carboxylic acids.
$C H_{3} C H_{2} O H P C C - -- \to C H_{3} C H O$

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Similar questions

$C H_{3} C H_{2} O H$ can be converted into $C H_{3} C H O$ by . . . .
(a) catalytic hydrogenation
(b) treatment with $L i A I H_{4}$
(c) treatment with pyridinium chlorochromate
(d) treatment with $K M n O_{4}$

Q. Assertion (A):

C H_{3} C H_{2} O H

can be converted into

C H_{3} C H O

by treatment with pyridinium chlorochromate.

Reason (R): PCC is a better reagent for oxidation of primary alcohols to aldehydes.
[1 Mark]

C H_{3} C H_{2} O H

can be converted into

C H_{3} C H O

by:

Q. The treatment of

(C H_{3})_{2} C = C H C H_{3}

with boiling

K M n O_{4}

produces :

Q. An organic compound

X

on treatment with pyridinium chlorochromate (PCC) in

C H_{2} C l_{2}

gives compound

Y .

Compound

Y

reacts with

I_{2} / N a O H

to form iodoform. The compound

X

is:

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CH3CH2OH can be converted into CH3CHO by:

The correct option is D treatment with pyridinium chlorochromatePyridinium chlorochromate (PCC), a complex of chromium trioxide with pyridine and HCl gives good yield of aldehydes and prevents further oxidation to carboxylic acids.CH3CH2OHPCC−−−→CH3CHO

$C H_{3} C H_{2} O H$ can be converted into $C H_{3} C H O$ by:

The correct option is D treatment with pyridinium chlorochromate
Pyridinium chlorochromate (PCC), a complex of chromium trioxide with pyridine and $H C l$ gives good yield of aldehydes and prevents further oxidation to carboxylic acids.
$C H_{3} C H_{2} O H P C C - -- \to C H_{3} C H O$